how will you connect three resister of resistance 2ohm 3ohm and 6 I'm to obtain total resistance of a40ohm b1ohm
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There are three resistors of resistances 2 Ω, 3 Ω, and 6 Ω respectively. Here, 6 Ω and 3 Ω resistors are connected in parallel. This equivalent resistor of resistance 2Ω is connected to a 2Ω resistor in series. Hence, the total resistance of the circuit is 4Ω
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