Question

How will you connect three resistors of 2 Ω, 3 Ω and 5 Ω respectively so as to obtain a resultant of 2.5 Ω? Draw the diagram to show the arrangement.; How will you connect three resistors of 2 Ω, 3 Ω and 5 Ω respectively so as to obtain a resultant of 2.5 Ω? Draw the diagram to show the arrangement.

Answer 1

Explanation:

We will have to link the resistors of values 2 Ώ  and 3 Ώ  in series to get the resistance of 2.5 Ώ and This configuration should be connected in parallel to the value of 5 Ώ  resistor.

Resistance 2 Ώ and 3 Ώ are the net resistance in series

$R= R_1+ R_2$

$R =2\Omega +3\Omega$

R = 5 Ω

This 5 Ω resistance is parallel to another 5 Ω resistance so its total resistance is:

$\frac{1}{R} =\frac{1}{R_1 } +\frac{1}{R_2 }$

$\frac{1}{R} =\frac{1}{5} + \frac{1}{5}$

$\frac{1}{R} =\frac{2}{5}$

R=2.5 Ω  

The combination's net resistance will be 2.5 Ω.

You can get all the answers of Chapter 1 in the link below:    

https://brainly.in/question/14961133

 

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