Question

how will you find reflection line by using perpendicular bisector. give an example.
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Answer 1

Answer:

It sounds like you're asking why the drawn line segment should happen to perpendicularly bisect the original line segment. Is that correct? If so, one principle which suffices to explain why this works is... symmetry.

That is, the entire setup is invariant under reflection across the original line (this reflection would send the original line's endpoints to themselves, the circular arcs to themselves, the arcs' points of intersection to each other, etc.). It is also invariant under reflection across the true perpendicular bisector (this reflection would send the original line's endpoints to each other, the circular arcs to each other, their points of intersection to themselves, etc.). Thus, the line segment drawn in the end must be invariant under these reflections as well, with the first of these reflections swapping it endpoints, while the latter keeps them fixed.

Answer 2

Step-by-step explanation:

I hope you understand that answer of this question with explanation.