Question

How will you find the six trigonometric ratios?

Answer 1

Answer:

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec). ...

sin C = (Side opposite to ∠C)/(Hypotenuse) = AB/AC.

cos C = (Side adjacent to ∠C)/(Hypotenuse) = BC/AC.

tan C = (Side opposite to ∠C)/(Side adjacent to ∠C) = AB/AC = sin ∠C/cos ∠C.

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Answer 2

Answer:

Answer:

Given :-

Current = 2.5 mA

Potential difference = 12 V

To Find :-

Resistance

Solution :-

Current = 2.5 × 10^-³

Now

Resistance = Potential difference/Current

Resistance = 12/2.5 10^{-3}10

−3

Resistance = 4.8 kΩ

Now

Given :-

Potential difference = 9 V

To Find :-

Current flow

Solution :-

At first the total Net resistance in the battery

0.2 Ω, 12 Ω, 0.3 Ω, 12 Ω,0.412 Ω,0.5 Ω, 12 Ω, 2.22 Ω

=> 49.632 Ω

Now

We know that

V = IR

By putting value

9 = I(49.632)

9/49.632 = I

0.18 = I