Math, asked by drthdate3670, 9 months ago

How will you formulate quadratic equations as illustrated in real life situation

Answers

Answered by shabanbegam143
0

Step-by-step explanation:

Example: Throwing a Ball

A ball is thrown straight up, from 3 m above the ground, with a velocity of 14 m/s. When does it hit the ground?

Ignoring air resistance, we can work out its height by adding up these three things:

(Note: t is time in seconds)

The height starts at 3 m: 3

It travels upwards at 14 meters per second (14 m/s): 14t

Gravity pulls it down, changing its position by about 5 m per second squared: −5t2

(Note for the enthusiastic: the -5t2 is simplified from -(½)at2 with a=9.8 m/s2)

Add them up and the height h at any time t is:

h = 3 + 14t − 5t2

And the ball will hit the ground when the height is zero:

3 + 14t − 5t2 = 0

Which is a Quadratic Equation !

In "Standard Form" it looks like:

−5t2 + 14t + 3 = 0

It looks even better when we multiply all terms by −1:

5t2 − 14t − 3 = 0

Let us solve it ...

There are many ways to solve it, here we will factor it using the "Find two numbers that multiply to give a×c, and add to give b" method in Factoring Quadratics:

a×c = −15, and b = −14.

The factors of −15 are: −15, −5, −3, −1, 1, 3, 5, 15

By trying a few combinations we find that −15 and 1 work (−15×1 = −15, and −15+1 = −14)

Rewrite middle with −15 and 1: 5t2 − 15t + t − 3 = 0

Factor first two and last two: 5t(t − 3) + 1(t − 3) = 0

Common Factor is (t − 3): (5t + 1)(t − 3) = 0

And the two solutions are: 5t + 1 = 0 or t − 3 = 0

t = −0.2 or t = 3

The "t = −0.2" is a negative time, impossible in our case.

The "t = 3" is the answer we want:

Answered by amitnrw
0

Given :  own real life problem that will lead to forming quadratic equation.

To Find : Formulate quadratic equation

Solution:

Product of my age 5 years before and my age after 5 years is  200

Find the present age.

Assume that Present age = x year

Age 5 years before = x - 5 years

After after 5 years = x + 5 years

Product of my age 5 years before and my age after 5 years is  200

=> (x - 5)(x + 5)  =  200

=> x² - 25 = 200

=> x² -225  = 0

Quadratic Equation :

ax² + bx  + c  = 0  where  a≠ 0

x² -225  = 0  is Quadratic Equation

a = 1 , b = 0  , c = - 225

x² -225  = 0

(x + 15)(x - 15) = 0

x = ± 15

as Age can not be negative

Hence present age is 15 years

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