Question

How will you join the resistor 3 ohma ,6 ohms, and 8 ohms to get an equivalent resistence of 10 ohms?

Answer 1

3ohm and 2ohm in parallel with 8 ohm in series

Answer 2

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I have join the 3 ohm and the 6 ohm resistance in parallel circuit. Then the equivalent resistance will be :

$\frac{1}{R} = \frac{1}{3} + \frac{1}{6} = \frac{(2 + 1)}{6} = \frac{1}{2}$

$\underline\green{ ᴛʜᴇʀᴇғᴏʀᴇ,}\: \: \: \ R =2 \: ohm$

Then I join the third resistance that is 8 ohm in series circuit so that the equivalent resistance will be :

R = 2 + 8 = 10 ohm.