Question

how will you prepare 0.02N sodium carbonate in 250 ml​

Answer 1

Answer:

Prepare a 0.2-M solution of anhydrous sodium carbonate (2.2 g/100 mL).

Prepare a 0.2-M solution of sodium bicarbonate (1.68 g/100 mL).

Combine 4 mL of carbonate solution from Step 1 and 46 mL of bicarbonate solution from Step 2.

Bring to 200 mL with H2O. Final pH will be 9.2.

Explanation:

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