How will you prepare 10%NaOH and calculate molarity of 10% of NaOH
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10gNaOH dissolve in 100g solution or 19g naOH is prepared in (100-10)=90g of water
therefore weight of NaOh ÷10g mol% wt . of NaOH =10/40= 1/4 =0.25
weight of solvent ( water ) =90g
mortality (m)
moles of NaOH ×1000 / wt. of water (in gram )
0.25 ×1000/90 = 2.778
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