How will you prepare a 0.5 M of Hydrogen chloride for your experiment
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C1V1= C2V2 We want to prepare 1l 0.5M HCl => 0.5*1; and we have to take x l of 11.8M HCl. =0.0424 l. So you have to take 0.0424l of conc HCl and 0.9576l of water.
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