How will you prepare a 35% methanol solution of 20 mL?
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found an article state that 80% acidified methanol was prepared using HCl/methanol/water, 1:80:10, v/v solution? The concentration of HCl used for the preparation was not specified, and this is beyond my mathematical understanding, can someone help me with the procedure for HCl acidified 80% Methanol solution preparation
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