Chemistry, asked by Shivamdhru1581, 10 months ago

How will you prepare acetone from methyl magnesium iodide

Answers

Answered by muhammadhamza16
7

acetone is obtained from grignard reagent by using acetaldehyde.

for example:

1st step:

CH3_CO_H + CH3_Mg_Br → CH3_CHCH3_O_Mg_Br (in the presence of polar solvent)

2nd step:

CH3_CHCH3_O_Mg_Br → CH3_CHOH_CH3 + HO_Mg_Br (in the presence of H+ / OH-)

3RD STEP:

CH3_CHOH_CH3 + [O] → CH3_CO_CH3 + H2O (IN THE PRESENCE OF Cu)

But this process is very expensive and unreliable. therefore it is not used to produce acetone which makes waste of time metarial and money.

HOPE YOU UNDERSTAND AND IT HELP YOU.

Answered by HarshChaudhary0706
0

Answer:

Explanation:

acetone is obtained from grignard reagent by using acetaldehyde.

for example:

1st step:

CH3_CO_H + CH3_Mg_Br → CH3_CHCH3_O_Mg_Br (in the presence of polar solvent)

2nd step:

CH3_CHCH3_O_Mg_Br → CH3_CHOH_CH3 + HO_Mg_Br (in the presence of H+ / OH-)

3RD STEP:

CH3_CHOH_CH3 + [O] → CH3_CO_CH3 + H2O (IN THE PRESENCE OF Cu)

But this process is very expensive and unreliable. therefore it is not used to produce acetone which makes waste of time metarial and money.

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