How will you prepare the 0.1 molar solution of oxalic acid (H2C2O4) in 250 ml from 2 molar stock solution?
Answers
Answered by
1
Answer:
n. factor for H2C2O4 =2
Equivalent weight =2M
Normality = equivalentweight×volume(inmL)weight×1000
0.1=(2126)×250weight×1000
Therefore, weight = 1.575g
Answered by
0
Answer:
Given that N=0.1Nin one litre. Now we get the amount of solute to be taken. Hence option A is correct. 1.575gof oxalic acid has to be taken to prepare 250mLof N10solution.
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