Math, asked by ATHUU, 1 year ago

how will you rationalise square root of 2 upon square root of 6 minus square root of 2

Answers

Answered by Anonymous
2
{√2/(√6-√2)}*{(√6+√2)/(√6+√2)}= {(√12+2)/4}

Hope, it's correct..........

Anonymous: Why you reported it
Answered by kvnmurty
0
\frac{\sqrt2}{\sqrt6-\sqrt2}\\\\=\frac{\sqrt2(\sqrt6+\sqrt2)}{(\sqrt6-\sqrt2)(\sqrt6+\sqrt2)}\\\\=\frac{(\sqrt3+1)}{2}

question is not clear.  you should use  parentheses



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