How will you show that (17 × 11 × 2) + (17 × 11 × 5) is a composite number?
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Hey there!
A number which has more than 2 factors is called a composite number .
We know that, For every number, One and itself are factors. To prove that a number is composite, you need to prove that it has a third factor other than itself and one.
So , Given
(17 × 11 × 2) + (17 × 11 × 5)
= 17 ( 11 * 2 + 11 * 5 )
= 17 ( 11 ( 2 + 5 ))
= 17 * 11 * 7
So, We see that given number (17 × 11 × 2) + (17 × 11 × 5) has 17 , 11 , 7 as its factors other than one and itself.
Hence, It is a composite number.
Therefore, (17 × 11 × 2) + (17 × 11 × 5) is a composite number.
A number which has more than 2 factors is called a composite number .
We know that, For every number, One and itself are factors. To prove that a number is composite, you need to prove that it has a third factor other than itself and one.
So , Given
(17 × 11 × 2) + (17 × 11 × 5)
= 17 ( 11 * 2 + 11 * 5 )
= 17 ( 11 ( 2 + 5 ))
= 17 * 11 * 7
So, We see that given number (17 × 11 × 2) + (17 × 11 × 5) has 17 , 11 , 7 as its factors other than one and itself.
Hence, It is a composite number.
Therefore, (17 × 11 × 2) + (17 × 11 × 5) is a composite number.
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