Question

how would i find 1+2+3+4+5+6+7 all the way to 100

Answer 1

Answer:

sum upto n consecutive digits = n *(n+1)/2

example : 1 + 2 + 3 + 4 + 5 + 6 + 7 = 7*8/2 = 28

so for n = 100 ; sum is 100*101/2 = 50*101 = 5050

Step-by-step explanation:

Answer 2

If we add 1 to 100 1+2+3+4+5+6+7+8+9

this way

we will get 5050