how would pressure change if (a) area is tripled keeping force constant (b) force is tripled keeping area constant
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We know that, Pressure = Force Applied / Area of contact
(a) If Area is tripled then,
Pressure' = Force / 3 × Area
=> Pressure' = 1/3 × Force / Area
=> Pressure' = 1/3 × Pressure
Therefore, new pressure would be equal to one third of the original pressure
(b) If force applied is tripled then,
Pressure = 3×Force / Area
Pressure' = 3 × Pressure
Therefore, new pressure would be equal to three times the original pressure.
Hope this helps!!
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