Question

How would the pressure change if area is doubled keeping force constant.

Answer 1

Given:

Area of contact is doubled keeping the pressure constant.

To find:

Change in pressure.

Calculation:

Pressure is a scalar quantity calculated by the ratio of the trust (or force ) and the surface area upon which the force acts.

Initially ;

$\sf{ \therefore \: P = \dfrac{F}{area}}$

Finally ;

$\sf{ \therefore \: P2 = \dfrac{F}{2 \times (area)}}$

Dividing the two equations :

$\sf{ \therefore \: \dfrac{ P2}{P} = \dfrac{1}{2} }$

$\sf{ = > \: P2 = \dfrac{1}{2} \times P}$

$\sf{ = > \: final \: pressure = \dfrac{1}{2} \times (initial \: pressure)}$

So, final answer is :

Final pressure becomes half of initial pressure when the area of contact is doubled.

Answer 2

Answer:

When the surface area is doubled, keeping the force constant, the pressure will decrease.