Question

How would the pressure change if area is half keeping thrust constant 

(a) doubled

(b) half

(c) tripled

(d) no change

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Answer 1

Relation b/w Pressure , thrust and area is given by ,

$\sf \bigstar\ \; \pink{Pressure=\dfrac{Thrust}{Area}}$

$\sf \bigstar\ \; \blue{P=\dfrac{F}{A}}$

If area becomes half keeping thrust constant ,

$\sf New\ pressure,P'=\ ?\\\\\sf New\ Area,A'=\dfrac{A}{2}\\\\\sf New\ Thrust,F'=F$

Since , Thrust is constant .

$\implies \sf P'=\dfrac{F'}{A'}\\\\\implies \sf P'=\dfrac{F}{\frac{A}{2}}\\\\\implies \sf P'=\dfrac{2F}{A}\\\\\implies \sf P'=2\left(\dfrac{F}{A}\right)\\\\\implies \sf \orange{P'=2P}\ \; \bigstar$

So , New pressure will be doubled .

Option (a) [ Doubled ]

Answer 2

Answer:

The thrust acting on an object per unit area is called the pressure on the surface. Mathematically, it can be written as :

P=\dfrac{F}{A}

Where,

F is the thrust or the force acting

A is the area

So, it is clear that the pressure is inversely proportional to the area.

If the area is doubled keeping the thrust constant, the pressure would be half as :

P'=\dfrac{F}{A/2}=2\ P

Hence, this is the required solution.

Explanation:

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