How would the pressure change if the area is doubled thrust remaining constant
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Case 1: thrust=pressure×area........(1)
Case 2:thrust=(pressure)'×(area)'
=(pressure)'×(2×area)...........(2)
eq. (1)÷(2),
1=pressure÷(pressure)'×2
1=pressure×1/(pressure)'×2
(pressure)'=pressure/2
Case 2:thrust=(pressure)'×(area)'
=(pressure)'×(2×area)...........(2)
eq. (1)÷(2),
1=pressure÷(pressure)'×2
1=pressure×1/(pressure)'×2
(pressure)'=pressure/2
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