Question

How would the pressure changes if a) the area is doubled keeping the thrust constant? b) the thrust is doubled keeping the area constant?

Answer 1

Pressure Depends On Applied Force(Thrust) And On The Area
a) the area is doubled keeping the truth constant then pressure decreases
For Example Pressure P=(Force /Area)
P=F/A
If Area Doubled And Thrust constant Then
P1(Pressure)=(F/2A)=P/2
Pressure Decrease That is Equal To The Half Of Original Or Initial Pressure
b) the thrust is doubled keeping the area constant then pressure increase
Actual or Initial Pressure P=F/A
When Thrust Doubled And Area Keeping Constant Then
P2=(2F/A)=2P
Pressure Increased Which Is equal To The Double Of The Actual Or Initial Pressure

Answer 2

Answer:

Pressure Depends On Applied Force(Thrust) And On The Area

a) the area is doubled keeping the truth constant then pressure decreases

For Example Pressure P=(Force /Area)

P=F/A

If Area Doubled And Thrust constant Then

P1(Pressure)=(F/2A)=P/2

Pressure Decrease That is Equal To The Half Of Original Or Initial Pressure

b) the thrust is doubled keeping the area constant then pressure increase

Actual or Initial Pressure P=F/A

When Thrust Doubled And Area Keeping Constant Then

P2=(2F/A)=2P

Pressure Increased Which Is equal To The Double Of The Actual Or Initial Pressure

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