Question

How would the pressure (exerted by a force on an area) change if-
(a) the area is doubled keeping the thrust constant?
(b) thrust is doubled keeping the area constant?​

Answer 1

Answer:

Explanation:

a) If the area is doubled keeping the force constant, then pressure will be halved.

(b) If force is doubled keeping area constant, then pressure will also be doubled.

Answer 2

a question answer

Pa=F/A ( here f is thrust)

if area is doubled

pa=f/2a

which mean pressure decreased

for example

area given 2m^2

force given 40N

then pa =40/2

pressure=20pa

if area doubled

then pa = 40/2×2.

40/4

10pa

pressure decreased

b question ans

pressure=f/a

if thrust doubled

pressure= 2f/a

for example

pressure = 40/2

20pa

thrust doubled

pressure= 40×2/2

80/2

40pa

hence pressure doubled