Question

how would the pressure (exerted by a force on an area) change if -thrust is doubled keeping the area contact

Answer 1

let pressure be p
and. new pressure be. p'
thrust be. F
Now

P=F/A
P'=2F/A. (new PRESSURE = 2×thrust/ area)
P'=2P. (new PRESSURE= 2×pressure)

THEREFORE PRESSURE WILL ALSO BE DOUBLED