Question

How would the pressure (exerted by a force on an area) change if-
(a) the area is doubled keeping the thrust constant?
(b) thrust is doubled keeping the area constant?
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Answer 1

Answer:

Explanation:

If the thrust is constant and area is doubled than pressure will become half. For ex. Thrust = 2N area = 2cm

P=?

P= T/A

= 2/2

= 1

If area is doubled i. e it becomes 4

P will be 2/4

=0.5 therefore half of initial

2) if thrust is doubled and area constant then

Takin previous eg

Initial p was 2N/m^2

If thrust is doubled T will be 4 N and area 2cmxcm

Therefore

P= T/A

=4/2

=2

Which double of initial