how would the pressure( exerting by a force on an area) change if-(a) the area is doubled keeping the thrust constant?(b) thrust is doubled keeping the area constant?
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(a) we can mathematically say that the pressure which is the product of Force that is perpendicular to the area and the area of the object.
That is P(vector) = Force(vector) / Area here
Here Force is the perpendicular force..........So
when the area is doubled keeping the thrust constant Pressure is halved
and
when the thrust is doubled keeping the area constant,Pressure is doubled.which can be intuitively understood also.
Do tell if any doubts,if not mark as brainly if it helped you.
That is P(vector) = Force(vector) / Area here
Here Force is the perpendicular force..........So
when the area is doubled keeping the thrust constant Pressure is halved
and
when the thrust is doubled keeping the area constant,Pressure is doubled.which can be intuitively understood also.
Do tell if any doubts,if not mark as brainly if it helped you.
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6
Answer:
we can make mathematically see that the pressure which is the product of the force that is perpendicular to the area and the area of object that is free vector is equal to 4 sector and by area hare hare force is the perpendicular 4 so when area is the blood pressure is old is hafte when the trust is downloaded keeping the thrust concept for constant pressure is the bird which can be intimately understand also
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