How would the real number -9 be written as a complex number in a + b i form?
a. 0 - 3i
b. 0 + 3i
c. -9 + 0i
d. -9 + i
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Answer:
answer is c. -9 +0i
Step-by-step explanation:
this is because of the rules of the maths for converting a number jnto iota form . hope it helps
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