how would you account for the difference in bond angles in h2o(104.5) and ch4 (109.5) when oxygen and carbon are sp3 hybridized?
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In CH4, there are four H atoms bonded with a C atom. Hence bong angle is same between all of the (=109.5°).
In H2O, there are two H atoms bonded with O atom and two lone pairs of the O atom. The lone pair electrons push the two H atoms away. Hence the bond angle between the H atoms decreases (=104.5°) while the bond angle between the Lone pairs and H atoms increase (>109.5°).
Hope it helps you.
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