How would you calculate oxidation number?
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1.the oxidation state of free element is always zero.
2.The O.S of monoatomic ion =charge of ion.
3.The O. S of H is + 1 but it is -1 ,if combined with less electrnegative element.
4. The O. S of O is usually -2 but it is -1 in peroxides.
5.TheO.S of group 1 ekements is +1 and that of group 2 elements is +2.
6.The O. S of group 17 elements in bibary compounds is -1.
7.The sum of the oxidation number of all the atoms i a neutral compound is 0.
8.The sum of the oxidation numbers in a polyatomic ion is equal to charge of an ion.
ex:NaSO4- to find out O.S of sulphur
firstly, let the value of x
The O. S of Na is +1 and that of O is -2.
So, it is as follows
+1 +x+4(-2)=0
+1+x-8=0
×+(-7)=0
x= +7
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