Question

how would you calculate the pH of 0.001 M NaOH?

Answer 1

NaOH is a strong base that dissociates completely 
Therefore [OH-] = [NaOH] = 0.001M 

First calculate the pOH of the solution : 
pOH = -log [OH-] 
pOH = -log 0.001 
pOH = 3.00 

pH = 14.00 - pOH 
pH = 14.00 - 3.00 
pH = 11.00

Answer 2

hey folk....

NaOH is a strong base that dissociates completely 
Therefore [OH-] = [NaOH] = 0.001M 

First calculate the pOH of the solution : 
pOH = -log [OH-] 
pOH = -log 0.001 
pOH = 3.00 

pH = 14.00 - pOH 
pH = 14.00 - 3.00 
pH = 11.00

Thank you
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