How would you calculate the pH of 0.001M of NaOH?
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NaOH is a strong base that dissociates completely
Therefore [OH-] = [NaOH] = 0.001M
First calculate the pOH of the solution :
pOH = -log [OH-]
pOH = -log 0.001
pOH = 3.00
pH = 14.00 - pOH
pH = 14.00 - 3.00
pH = 11.00
Good Luck :)
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