How would you calculate the pH of the 0.39 M NH3 / 0.73 M NH4Cl buffer system?
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The pKa of NH+4 , the ion in NH4Cl , is about 9.26 , so we can proceed to calculate the pH :
pH=9.26+log(0.39 M0.73 M) ≈8.99.
pOH=4.74+log(0.73 M0.39 M) ≈5.01.
pH=14−pOH. =14−5.01≈8.99 .
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