Question

How would you determine the standard electrode potential of system $\large\tt { Mg ^{2+} | Mg }$​

Answer 1

Explanation:

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Answer 2

Answer:

The standard electrode potential of Mg2+| Mg can be measured with respect to the standard hydrogen electrode, represented by Pt(s), H2(g)(1 atm) | H+(aq) (1 M).

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.Eø = EøR - EøL

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.Eø = EøR - EøLHere,EøR for the standard hydrogen electrode is zero.

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.Eø = EøR - EøLHere,EøR for the standard hydrogen electrode is zero.∴ Eø = 0 - EøL

A cell, consisting of Mg | MgSO4(aq 1 M) as the anode and the standard hydrogen electrode as the cathode, is set up.Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.Eø = EøR - EøLHere,EøR for the standard hydrogen electrode is zero.∴ Eø = 0 - EøL= - EøL