how would you distinguish between copper ii oxide and carbon
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Copper (II) oxide and carbon will react as follows. Note that this is an example of a single displacement reaction.
2CuO + C → 2Cu + CO2
If you do the oxidation numbers, the copper in CuO has an oxidation number of +2. This should become evident when you think about the chemical makeup of the compound. It’s composed of ionic copper, which has a charge, and therefore oxidation number, of +2.
The reaction at equilibrium produces solid, metallic copper. Note that the copper has no charge and is by itself, so it has an oxidation number of 0.
The oxidation state of the copper went from +2 to 0, hence the copper was reduced.
The carbon begins with an oxidation number of 0. Note that it’s by itself without charge. At equilibrium it forms CO2, which gives carbon an oxidation state of +4. The oxidation state of carbon went from 0 to +4, hence the carbon was oxidized.
Because one reactant (copper) was reduced and another (carbon) was oxidized, it is a redox reaction.
2CuO + C → 2Cu + CO2
If you do the oxidation numbers, the copper in CuO has an oxidation number of +2. This should become evident when you think about the chemical makeup of the compound. It’s composed of ionic copper, which has a charge, and therefore oxidation number, of +2.
The reaction at equilibrium produces solid, metallic copper. Note that the copper has no charge and is by itself, so it has an oxidation number of 0.
The oxidation state of the copper went from +2 to 0, hence the copper was reduced.
The carbon begins with an oxidation number of 0. Note that it’s by itself without charge. At equilibrium it forms CO2, which gives carbon an oxidation state of +4. The oxidation state of carbon went from 0 to +4, hence the carbon was oxidized.
Because one reactant (copper) was reduced and another (carbon) was oxidized, it is a redox reaction.
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