Chemistry, asked by mvramana5867, 1 year ago

How would you distinguish experimentally between an alcohol and a carboxylic acid on the basis of physical and chemical properties

Answers

Answered by Veena1111
13
Heya User!!

Here is ur answer


To distinguish experimentally between an alcohol and a carboxylic acid on the basis of their physical and chemical property following methods can be used....

1) The carboxylic acid smells such as vinegar it has a pungent odour

2) whereas in contrast alcohol such as ethanol is sweet smelling.

3) carboxylic acid turns blue litmus red

4) alcohol turns red litmus blue

5) when phenolphthalein is added in carboxylic acid it remains colourless

6) when phenolphthalein is added to alcohol it turns into pink colour

7) alcohol does not react with sodium bicarbonate.

8) carboxylic acid reacts with sodium bicarbonate to produce CO2,H2O and salt..

9) carboxylic acid reacts with metals to produce H2 gas.....

10) carboxylic acid have -COOH as their functional group

11) alcohol has -OH as their functional group...


If it helps u then pls mark it as brainliest


Regards
Divya

^_^






Answered by Veena1111
3
Heya User!!

Here is ur answer


To distinguish experimentally between an alcohol and a carboxylic acid on the basis of their physical and chemical property following methods can be used....

1) The carboxylic acid smells such as vinegar it has a pungent odour

2) whereas in contrast alcohol such as ethanol is sweet smelling.

3) carboxylic acid turns blue litmus red

4) alcohol turns red litmus blue

5) when phenolphthalein is added in carboxylic acid it remains colourless

6) when phenolphthalein is added to alcohol it turns into pink colour

7) alcohol does not react with sodium bicarbonate.

8) carboxylic acid reacts with sodium bicarbonate to produce CO2,H2O and salt..

9) carboxylic acid reacts with metals to produce H2 gas.....

10) carboxylic acid have -COOH as their functional group

11) alcohol has -OH as their functional group...


If it helps u then pls mark it as brainliest


Regards
Divya

^_^






Similar questions