How would you make 120 mL of a 0.10 M solution of potassium hydroxide in water? We would dissolve --------gram of KOH in a volume of water that is less than 120 mL, and then add sufficient water to bring the volume of the solution up to 120 mL
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How would you make 120 mL of a 0.10 M solution of potassium hydroxide in water? (0.120 L) × (0.10 mol L–1) = 0.012 mol. We would dissolve this weight of KOH in a volume of water that is less than 120 mL, and then add sufficient water to bring the volume of the solution up to 120 mL
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