Question

How would you prepare 1.0 x 102 mL of 2.0 N HCl, starting with concentrated 12.0N HCl?

Answer 1

Answer:

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Answer 2

Preparation of 1.0 × 10²ml of 2.0N HCl

Explanation:

• To prepare 1.0 × 10² ml solution of 2.0N HCl, firstly we require to determine the volume of 12.0N HCl. Formula used to determine the volume of 12.0N HCl is
• M₁ × V₁ = M₂ × V₂
• here, M₁ = concentration of 2.0N HCl

                  V₁ = volume of 2.0N HCl (=1.0 × 10² ml)

                  M₂ = concentration of 12.0N HCl

                  V₂ = volume of 12.0N HCl

• Now, putting all the values we get,

              2.0N × 1.0 × 10²ml = 12.0N × V₂

                 $V_2 = \frac{2.0 \times 1.0 \times 10^2}{12.0}$

                 V₂ = 16.7 ml

• Therefore, 16.7ml is required to prepare 2.0N HCl solution.