how would you prepare 300 g of aqueous solution containing 10% mass by mass of sucrose?
pls help me with the answer plss. its urgent please
Answers
Given,
Total mass of the aqueous solution is 300 grams.
The percentage of the solute or the sucrose in the whole aqueous solution is 10%.
To find,
The mass of the solute and the solvent.
Solution,
We have to calculate the mass of the sucrose in the given aqua solution by using the following mathematical formula.
Mass percentage = 100 × Mass of solute/Mass of solution
Let,the mass of solute = x grams
[Here,x is a variable to do the further mathematical calculations.]
So,by putting the given values,we get the following mathematical equation :
10 = 100 × x/300
10 = x/3
x/3 = 10
x = 30
Solute = 30 grams
Solvent = 300-30 = 270 grams
Hence,there will be 30 grams of sucrose and 270 grams of water in the whole aqueous solution.
(And,we just need to mix 30 grams of sugar and 270 grams of water with each other,to make the aqueous solution according to the given data in the question.)