How would you prepare 50ml of 1 N solution of potassium chloride?
Answers
Answered by
0
Answer:
Correct option is
C
3.73 g
50 ml of 1 M solution of KCl contains 0.05×=0.05 moles.
Weight = Moles × molar mass
Weight of KCl = 0.05×74.5=3.73 g
Hence, option C is correct.
Explanation:
pls add me in brainleast
Answered by
0
Answer:
c is the correct answer
mark me as brainliest please
Similar questions