Question

How would you prepare a liter of “carbonate buffer” at a pH of 10.10? You are provided with carbonic acid (H2CO3), sodium hydrogen carbonate (NaHCO3), and sodium carbonate (Na2CO3).

Answer 1

Answer:

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Explanation:

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Answer 2

The prepare a liter of carbonate buffer at a $620mL$.

Explanation:

The closest $p^{k}a$ to $p^{H}=10.10$

$K_{a}=4.8*10^{-1}$ $p^{k}a=10.32$

so we cause the $\frac{HCO_{3}^{-}}{CO_{3}^{2-}}$

$P^{H}=p^{k}a+log_{10}\frac{[CO_{3}^{2-}]}{[HCO_{3}^{-}]}$

$p^{k}a-p^{H}=-log_{10}\frac{[CO_{3}^{2-}]}{[HCO_{3}^{2-}]}$

$10.32-10.10=0.22=log\frac{[HCO_{3}^{-}]}{[CO_{3}^{2-}]}$

$1.000L=V_{HCO_{3}^{-}+V_{CO_{3}^{-}$

$1.000L=2.7V_{CO_{3}^{-}$

$V_{CO_{3}^{-}=380mL$

$V_{HCO_{3}^{-}=620mL$.