Question

How would you prepare following compounds from an internal alkyne? Give the mechanism of

the reactions.

(i) 3-Hexanone

(ii) Ethanoic acid​

Answer 1

Answer:

Hey mate here are you answers

Explanation:

3-hexanone

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structural formula would be like this- Ch3-ch2-ch2-c--o-ch2-ch3 (-- this refers to double bond)

Refer to the attachment for 3-Hexanone

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Now Ethanoic acid is as follows

Structural formula of Ethanoic acid- Ch3cooh or Ch3c--oh (-- refers to double bond)

Refer to the attachment for Ethanoic acid

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Answer 2

Answer:

Explanation:

For the first part you make use of hex-3-yne and you add Hg2+ and dilH2SO4 which will form hex-3-enol. This in turn can tautomerise to give 3-hexanone.

For getting ethnic acid I would recommend using butan-2-yne and oxidative ozonylisis after reducing yne to ene