Question

How would you separate a mixture of NH4CI and I2

Answer 1

Principle:I2 is soluble in ethyl alcohol (C2H5OH) while NH4Cl is not.
Process 1 : Dissolution in a special solvent,i.e.Ethyl alcohol.

Iodine will dissolve within the solvent and NH4Cl crystals will be found floating on the surface of the liquid.

Process 2:Filtration

The mixture will be filtered and NH4Cl will be obtained on the filter paper.

Process 3:Evaporation

The subsequent filtrate will be evaporated to get the precipitate of Iodine.

Answer 2

We can separate by evaporation and filtration