How would you solve 4x+8y=-4,-5x+3y=-21 with substitution?
Answers
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Answer:x =19\7 and y = 16\7
Step-by-step explanation:
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We need to eliminate either x or y to solve the equation
So multiplying first equation by 5
20x+40y=-20---p
Multiply second equation by 4
-20x+12y=-84---q
Adding equation p and q
52y =-104
y=(-104/52)=-2
y=-2
Substitute y=-2 in 1st equation
4x+(8*-2)=-4
4x-16=-4
4x=16-4=12
x=3
Solution is
x=3 y=-2
So multiplying first equation by 5
20x+40y=-20---p
Multiply second equation by 4
-20x+12y=-84---q
Adding equation p and q
52y =-104
y=(-104/52)=-2
y=-2
Substitute y=-2 in 1st equation
4x+(8*-2)=-4
4x-16=-4
4x=16-4=12
x=3
Solution is
x=3 y=-2
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