How would you use screw gauge to
Calculate the diameter of a bob
having mass m. why it is different
from on ordinary vernier Calipers?
Answers
Here is your answer:
How much we know about the Vernier calipers?
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How much we know about the Vernier calipers?
Measurement is a fundamental part of all scientific experiments, including Physics. At one extreme, our vast universe extends this measuring exercise to light-years, the distances so vast that we cannot see them from our eyes. On the other extreme of the smallest distances, new discoveries are pushing it down to femto-meter (10-15 m) or even less. These distances are so small that we cannot see them from our eyes. At every 1-2 order of magnitude change in distance, our instruments to measure the distances accurately can differ. When the distances, we want to measure, are in the range of 10-2 mm to 1 mm, we use Vernier Calipers and Screw Gauge for precise measurement. In this article, we are going to focus on these measuring instruments only.
In class 11th Physics lab, we were trained to answer the following questions:
How to find the Least Count (LC) or Vernier Constant?
How to read Main Scale Reading (MSR) and Vernier Scale Reading (VSR)?
How to find the zero error?
How to use the above data to get the final measurement?
Answers to these how to questions kept us content for 22 years. But this was not adequate to solve the IIT JEE 2016 problem. We needed to figure out some more interesting why questions like:
Why least count is the ratio of "value of 1 Main Scale Division" to the "Total number of divisions on the vernier scale".
Why the measured value is given by: Observed Value = MSR + LC×VSR.
Why the zero error is subtracted from the observed value i.e., True Value = Measured Value - Zero Error.
Explanation:
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