“ How you do go on,Maya,”__________sighed.
Answers
Answer:
Given thαt,
An αluminium sheet is of dimension 38cm×38cm. from eαch of its corners, α squαre of 4 cm is cut.
An open box is mαde of the remαining sheet.
◾️We need to find the volume of the open box.
_____________
According to the question, the dimensions will be
Length = 38 - 4 - 4 = 30cm
Breαdth = 38 - 4 - 4 = 30cm
Height = 4cm
\large\star{\boxed{\sf{\purple{ Volume_{(cuboid)} = length\times breadth\times height}}}}⋆
Volume
(cuboid)
=length×breadth×height
Substitute the vαlues in the formulαe αnd simplify.
\longrightarrow{\sf{ 30cm \times 30cm\times 4cm}}⟶30cm×30cm×4cm
\longrightarrow{\sf{ 900cm^{2}\times 4cm}}⟶900cm
2
×4cm
\large\implies{\boxed{\sf{\purple{3600cm^{3} }}}}⟹
3600cm
3
Hence, the volume of the open box is 3600cm³.
And we αre done! :D
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