Howmanynumbers lie between 10 and300,which when divided byby 4leave a remainder3?
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In fact we have to find 'n' that is the number of terms of the AP.
an = a + (n - 1)d
299 = 11 + (n -1)4
299 = 11 + 4n - 4
299 - 11 + 4 = 4n
292 = 4n
n = 292/4
n = 73
So, total 73 numbers lie between 10 to 300 which when divided by 4 leaves a remainder 3.
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