Hsjskdkdkajsbekshsbsolve maths
Attachments:
Answers
Answered by
5
dx/(4+5sinx)
divide N and D by cos x
sec x dx / 4secx + 5 tanx
let 4 sec x +5 tan x= t
4 secx tanx + 5 sec^2x ) dx = dpt
secx ( 4 tan x + 5 sec x) dx= dt
secx t dx = dt
secx dx = dt/t.
So dt/t × t
dt/t^2
-1/t
-1/4sec x + 5 tanx
divide N and D by cos x
sec x dx / 4secx + 5 tanx
let 4 sec x +5 tan x= t
4 secx tanx + 5 sec^2x ) dx = dpt
secx ( 4 tan x + 5 sec x) dx= dt
secx t dx = dt
secx dx = dt/t.
So dt/t × t
dt/t^2
-1/t
-1/4sec x + 5 tanx
Answered by
0
1/4sec X +5 tan X...........
Similar questions