Question

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Answer 1

A = P(1 + rn)

Find the number of years when both amount will be equal:

8000( 1 + 0.12n) = 9100(1 + 0.1n)

8000 + 960n = 9100 + 910n

960n - 910n = 9100 - 8000

50n = 1100

n = 22 years

Answer: (c) 22 years

Answer 2

$\huge {\bold {Solutions:-}}$
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Q: A borrows ₹ 8000 at 12% per annum simple interest and B borrows ₹ 9100 at 10% per annum simple interest. In how many years will their amount be equal ?
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We know that,
A = P(1 + rn)


The no. of years when both amount will be equal =>

=> 8000( 1 + 0.12n) = 9100(1 + 0.1n)

=> 8000 + 960n = 9100 + 910n

=> 960n - 910n = 9100 - 8000

=> 50n = 1100

=> n = 22 years

Hence,

Your answer is $\bold {\underline {(c)~22~years}}$