Question

Htan object, starting from rest, moves in a straight line with an acceleration that is given by . Find the distance travelled during the first 9 seconds.

Answer 1

Distance = (Initial velocity * time)+(1/2 * Acceleration * Time^2)

Assume ‘a' as a constant acceleration

For first 10 seconds,S1 = (0*10)+(1/2*a*10^2)

= 0+( 50a)

= 50a

In first 10 sec body will move 50a distance.

After the 10 sec velocity of the body,

Final Velocity = Initial Velocity +(Acceleration*Time)

v = 0+ (a*10)

= 10a

Next 10 sec,

Distance = (Initial velocity * time)+(1/2 * Acceleration * Time^2)

S2 = (10a*10)+(1/2*a*10^2)

= 100a+50a

= 150a

S1 is not equal to S2 (S1 = 50a , S2 = 150a)