Chemistry, asked by sahanakavana0205, 1 month ago

hu
4. The average atomic mass of copper is 63.55 amu. If the only two isotopes of
copper have masses of 62.94 amu and 64.93 amu, what are the percentages of
each?​

Answers

Answered by 231001ruchi
6

Answer:

copper has two naturally occurring isotopes, copper-63 and copper-65. This means that their respective decimal abundance must add up to give 1.

If you take x to be the decimal abundance of copper-63, you can say that the decimal abundance of copper-65 will be equal to 1−x.

Therefore, 

Copper-63x⋅62.9296u+ copper-65(1−x)⋅64.9278u=63.546u

Solve this equation for x to get

62.9296⋅x−64.9278⋅x=63.546−64.9278

1.9982⋅x=1.3818⇒x=1.38181.9982=0.69152

This means that the percent abundances of the two isotopes will be

● 69.152%→63Cu

● 30.848%→65Cu

Explanation:

here is your answer please mark me in brainlist and give me many thanks please.

Answered by Manjula29
1

As we all know, Copper consist of two isotopes:-

  • copper-63
  • copper-65

On the basis of this, we can infer that the sum of their respective decimal abundance is 1.

Now, let x be the decimal abundance of copper-63

∴ decimal abundance of copper-65 = 1 − x

Now, [Copper-63x ⋅ 62.9296 u] + [copper-65(1−x) ⋅64.9278 u] = 63.546 u

To find the value of x, we will have to solve the following equation;

[62.9296 ⋅ x − 64.9278 ⋅ x] = [63.546 − 64.9278]

⇒ 1.9982 ⋅ x = 1.3818

⇒ x = 1.3818 ÷ 1.9982

⇒ x = 0.69152

∴ The percentages of abundances of each of the two isotopes are;

69.152% = 63 Cu

30.848% = 65 Cu

Ans) 69.15% = 63Cu; 30.84% = 65Cu

Similar questions