Biology, asked by kanthac069, 8 months ago

Human body requires 2370 K. Cal of energy
daily. The heat of combustion of glucose is
-790 K.cal/mole. The amount of glucose
required for daily consumption is​

Answers

Answered by vanshdubey
1

Answer:

Moles for 2370K cal =

790

2370

moles

C

6

H

2

O

16

= 72+12+96

= 84+96

= 180

180g

Amountofglucose

=moles=

79ϕ

237ϕ

Amount of glucose =

79

237

×180g

=540g

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