Question

Humid air breaks in electric field of 3×10^6 N/C what is the magnitude of electric force on electron and for ion?​

Answer 1

Explanation:

we know that :

Fi = Eqion = Ee

= [3.0 * 10^6 N/C ] [1.6 * 10-^19]

= 4.8 * 10-^13N